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150x+10000=-2x^2+600x
We move all terms to the left:
150x+10000-(-2x^2+600x)=0
We get rid of parentheses
2x^2-600x+150x+10000=0
We add all the numbers together, and all the variables
2x^2-450x+10000=0
a = 2; b = -450; c = +10000;
Δ = b2-4ac
Δ = -4502-4·2·10000
Δ = 122500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{122500}=350$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-450)-350}{2*2}=\frac{100}{4} =25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-450)+350}{2*2}=\frac{800}{4} =200 $
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